I propose John (someday I should write about it) the following game:
5, 4, 2, 3, 1
are the numbers 1 to 5 ordered by some criterion diabolical. If we add the numbers six, seven and eight, the sequence becomes:
5, 4, 2, 8, 6, 7, 3, 1
And when you add nine and ten: 5 , 4, 10, 2, 9, 8, 6, 7, 3, 1
The challenge is to find that view diabolical. The answer, as always in the comments or in a post within a week.
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